104.二叉树的最大深度

题目描述

给定一个二叉树 root ,返回其最大深度。

二叉树的 最大深度 是指从根节点到最远叶子节点的最长路径上的节点数。

示例 1:

img

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输入:root = [3,9,20,null,null,15,7]
输出:3

示例 2:

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输入:root = [1,null,2]
输出:2

提示:

  • 树中节点的数量在 [0, 104] 区间内。
  • -100 <= Node.val <= 100

题解

深度优先遍历

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/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public int maxDepth(TreeNode root) {
if (root == null) {
return 0;
}
return Integer.max(maxDepth(root.left), maxDepth(root.right)) + 1;
}
}

提交:

深度优先遍历

广度优先遍历

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/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public int maxDepth(TreeNode root) {
Queue<TreeNode> queue = new LinkedList<>();
if (root != null) {
queue.add(root);
}
int ans = 0;
while (!queue.isEmpty()) {
int size = queue.size();
ans++;
for (int i = 0; i < size; i++) {
TreeNode poll = queue.poll();
if (poll.left != null) {
queue.add(poll.left);
}
if (poll.right != null) {
queue.add(poll.right);
}
}
}
return ans;
}
}

提交:

广度优先遍历